What is the potential difference across a 12.0 mH inductor if the current through the inductor drops from 140 mA to 60.0 mA in 14.0 μs ?

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EXPERT ANSWER

emf is given by

E = L di/ dt = 0.012* (140 – 60)* 10^-3 / (14* 10^-6)

E = 68.57 V

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option (a) is correct