## EXPERT ANSWER

**Solution::**

The hypothesis are given by,

**The null hypothesis is given by,**

**The alternative hypothesis is given by,**

**Here we apply chi square goodness of fit test.**

O | E | ||||

Straight | 72 | 60 | 12 | 144 | 2.4 |

Right Turn | 45 | 60 | -15 | 225 | 3.75 |

Left Turn | 63 | 60 | 3 | 9 | 0.15 |

Total | 180 | 180 | 0 | 378 | 6.3 |

The value of test statistic is given by,

**O: for observe frequency**

**E: for expected frequency**

**So the value of test statistic is 6.3**

**The critical value is given by,**

[Critical value we obtain from using sowtware]

**Decision about the null hypothesis**

Here the value of test statistic is greater than critical value.

i.e, The value of test statistic fall under critical region.

So we reject the null hypothesis.

**Conclusion::**

There is no equal proportion of car in three direction at 10% level of significance.