The hypothesis are given by,
The null hypothesis is given by,
The alternative hypothesis is given by,
Here we apply chi square goodness of fit test.
The value of test statistic is given by,
O: for observe frequency
E: for expected frequency
So the value of test statistic is 6.3
The critical value is given by,
[Critical value we obtain from using sowtware]
Decision about the null hypothesis
Here the value of test statistic is greater than critical value.
i.e, The value of test statistic fall under critical region.
So we reject the null hypothesis.
There is no equal proportion of car in three direction at 10% level of significance.