Use the completeness axiom for sups to prove the analogous result for infs: if S is a subset of Real Numbers, S ≠ Ø, and S is bounded below, then there is a α existent in REAL NUMBERS such that α = inf(S). (Hint: Given a nonempty set S, look at the new set -S defined by -S = {-s|s is existent in S}. Apply the completeness axiom to -S and interpret the result.)

39 0

Get full Expert solution in seconds

$1.97 ONLY

Unlock Answer

EXPERT ANSWER

Leave a Comment

Your email address will not be published. Required fields are marked *