## EXPERT ANSWER

1. Here it is given that

Use W14×61

Fy = 50ksi

Now, design strength of column AB

Pu = 2658.45k

Design Strength of column AB = 2658.45k

2. Let us first design column AB and then Base plate design must be done

Assuming both ends fixed. The effective length is 0.65×16 10.4 feet.

Using LRFD, the factored load is Pu=1.2×350+1.6×450=1,140kips

section | weight | Area(in^2) | Imin | lambda | Fe | Fcr |

W14X74 | 74 | 21.8 | 2.48 | 50.32258 | 113.0243 | 41.54859 |

W14X82 | 82 | 24 | 2.48 | 50.32258 | 113.0243 | 41.54859 |

W14X90 | 90 | 26.5 | 3.7 | 33.72973 | 251.5776 | 46.00904 |

W14X99 | 99 | 29.1 | 3.71 | 33.63881 | 252.9393 | 46.02965 |