## EXPERT ANSWER

b)

Cycle time = Available time / Required production = 480 / 50 = **9..60** minutes

c)

Sum of the task times = (4+6+7+6+6+8+8+6) = 51 minutes

Cycle time = 9.6 minutes

So, the theoretical minimum number of stations = 51/9.6 = 5.3 i.e. **6 stations**

d)

Task | Workstation # |

A | Station-1 |

B | Station-2 |

C | Station-3 |

D | Station-4 |

E | Station-5 |

F | Station-6 |

G | Station-7 |

H | Station-8 |

e)

The total idle time per cycle (considering the improved cycle time of 8 minutes) = **13** minutes per cycle

f)

Total idle time in 8 hours = 13 minutes per cycle * No. of cycles = 13 * (8*60 / Actual cycle time) = 13*8*60/8 = **780** minutes