(discreate math)

Determine the number of integer solutions for

x_{1}+x_{2}+x_{3}+x_{4}+x_{5} < 40

where

x_{i} >= 0, i =[1,5]

for a, the answer is C(44 39) and says it is the same solution for x_{1}+x_{2}+x_{3}+x_{4}+x_{5}+x_{6} = 39