Convert the given system to an augmented matrix. 2×1 8×2 4×3 12 -x1 3×2 5×3 5 -1 -3 5 12 2 8-4 -1 -3 5 12 2 8 -4 12 -1 -3 5 12 2 8-4 12 Find all solutions by reducing the system to echelon form and back substituting. (If there are an infinite number of solutions use s1 as your parameter. If there is no solution, enter NO SOLUTION.) MO SOLUTION x X1, X2, X3) eBook

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