Physics

Data Table 3: Diameter of Solid Cylinder Trial Main Scale (mm) 1 Vernier Coincidence Diameter of Cylinder (mm) Mean Diameter (cm) 2 3 4 4 8 1/128 in 3 0 2 50 10 20 30 40 80 60 70 90 1681 0.05mm 10 15 20

fill out ENTIRE table please and explain how vernier coincidence is calculated properly EXPERT ANSWER Sol: In Vernier calipers, there are two scales one is Main Scale and other is Vernier Scale, and here least count is 0.05mmNow to find main scale reading we should see the division of main scale which is just left side …

Data Table 3: Diameter of Solid Cylinder Trial Main Scale (mm) 1 Vernier Coincidence Diameter of Cylinder (mm) Mean Diameter (cm) 2 3 4 4 8 1/128 in 3 0 2 50 10 20 30 40 80 60 70 90 1681 0.05mm 10 15 20 Read More »

A=0xL Record the calculated value for A in Data Table 5. – The arc length equation requires the angle to be measured in radians: 0° X TT / 180° = (rad). Calculate the maximum potential energy for the 1.00 m length pendulum with the 50 g pendulum bob displaced to 10° using the equation: Umaz = 3 (129) A Record the calculated value for Umax in Data Table 5. Calculate the maximum kinetic energy for the 1.00 m length pendulum with the 50 g pendulum bob displaced to 10° using the equation: Kur = 3″ ( 274)” Record the calculated value for Kmax in Data Table 5. Calculate the percent difference between the maximum kinetic energy and maximum potential energy using the equation: g (graph) (m/s) % Error (graph) Data Table 4: Acceleration Due to Gravity for 0 = 10°, m = 50 g Length Period squared g (calculated) Ag (calculated) % Error (m) (m/s) (m/s) (m/s) (calculated) 1.50 5.12m/s^2 11.57m/s^2 0.11m/s^2 5.4% 12.3m/s^2 25.3% 1.00 3.44m/s^2 11.47m/s^2 0.14m/s^2 16.1% 0.50 1.91m/s^2 10.34m/s^2 0.17m/s^2 17.91% Data Table 3: Mass and Period for 0 = 10°, L = 1.0 m Time 1 (s) Time 2 (s) Time 3 (s) Average time (s) Period (s) Observations Mass (9) 50 18.6s 18.55 18.6s 18.6s 1.95 100 18.45 18.55 18.64s 18.515 1.95 150 18.75 18.73s 18.64s 18.75 1.95 Data Table 5: Energy for 0 = 10°, m = 50 g, L = 1.00 m Amplitude (m) Umax (J) Kmax (J) % Difference

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Question 1 (0.5 points) The equation for the period of a pendulum reduces to T = 271 for small angles less than 30 degrees. According to Equation 1 in our lab manual, how big a correction will the next term in the series expansion give us. (You have to plug in numbers to answer this question). O 10% O Greater then 5% but less than 10% O Greater than 2% but less than 5% O~ 1.67%

What type of exchange occurs during the swing motion of a pendulum? A. Position is exchanged for frequency B. Height is exchanged for amplitude C. Kinetic energy is exchanged for potential energy D. Speed is exchanged for acceleration Why is the mass of ‘bob’ not crucial for pendulum? Because the period is independent of the …

Question 1 (0.5 points) The equation for the period of a pendulum reduces to T = 271 for small angles less than 30 degrees. According to Equation 1 in our lab manual, how big a correction will the next term in the series expansion give us. (You have to plug in numbers to answer this question). O 10% O Greater then 5% but less than 10% O Greater than 2% but less than 5% O~ 1.67% Read More »

0.05mm Data Table 2: Diameter of a Sphere Trial Main Scale (mm) Vernier Coincidence Diameter of Marble (mm) Mean Diameter (cm) 20.00mm 20.00mm 20.00mm 20.00mm 0 48 10 – 30 40 50 ) 60 70 * 30 ررررررررررررررر 11111111111111111 0 1 2 3 4 5 6 7 8 9 0.05mm Data Table 3: Diameter of Solid Cylinder Trial Main Scale (mm) Vernier Coincidence Diameter of Cylinder (mm) Mean Diameter (cm) 23.00mm 2 23.00mm 23.00mm 23.00mm 0 20 60 סך ויןיןיןיןיןיןיןזי 4 6 7 8 9 0.05mm Data Table 4: Height of Solid Cylinder Trial Main Scale (mm) Height of Cylinder (mm) Mean height (cm)

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Data Table 2: Length and Period for 0 = 10°, m = 50 g Time 2 (s) Time 3 (s) Period (s) Observations Length Time 1 (s) (m) 1.50 25.76 Average time (s) 26 26 22.92 2.6 Slow speed 1.00 22.22 22.40 21 21.87 2.2 medium spee 0.50 15.74 15.30 16 15.68 1.6 High speed Data Table 4: Acceleration Due to Gravity for 0 = 10°, m = 50 g Length Period g Ag % Error g (graph) (m) squared (calculated) (calculated) (calculated) (m/s2) (m/s) (m/s) (m/s) 1.50 % Error (graph) 1.00 0.50 33 Calculate the square of the period for the three different pendulum lengths recorded in Data Table 2 and record the value in Data Table 4. 34 Calculate the acceleration due to gravity for the 1.50 m, 1.00 m and 0.50 m pendulum lengths using the T values calculated in step 33 and the equation: 472L T2 35 Record the calculated values for g in Data Table 4. 36 Calculate the uncertainty in your calculated values of the acceleration due to gravity using estimates of the uncertainty in time and distance measurements based on your experimental procedure: Ag=9[(247) +(4) 37 Record the calculated values for Ag in Data Table 4. 38 Calculate the percent error between each of your calculated values for the acceleration due to gravity and the accepted value of 9.81 m/s2: Percent Error = Measured Value – Accepted Value Accepted Value x 100% 39 Record the calculated values for Percent Error in Data Table 4. 40 Use graphing software to generate a graph of Length on the vertical axis versus Period Squared on the horizontal axis.

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1. Determine the position in the oscillation where an object in simple harmonic motion: a. has the greatest speed. b. has the greatest acceleration. c. experiences the greatest restoring force. d. experiences zero restoring force. B т TE 2. Describe simple harmonic motion, including its cause and appearance. B T T Type here to search

EXPERT ANSWER 1. (a) greatest speed at the equilibrium position (b) the greatest acceleration at the extreme position. (c) the greatest restoring force at the extreme position (d) Zero restoring force at the equilibrium position. 2. Simple harmonic motion is a type of oscillatory motion in which the Acceleration of the object at an instant …

1. Determine the position in the oscillation where an object in simple harmonic motion: a. has the greatest speed. b. has the greatest acceleration. c. experiences the greatest restoring force. d. experiences zero restoring force. B т TE 2. Describe simple harmonic motion, including its cause and appearance. B T T Type here to search Read More »