# Calculate 4(x, t)|2 from (15.50) and show that the wave packet moves uniformly and at the same time spreads so that h22 (Ax)} = (4x) | 1 + (15.51) 4m²(Ax) -1/2 4(x, t) = [2 (Axhâ] – 1/4 iħt 1 + 2m(4x)? exp x2 ħt + ikox – iko 4(4x) 2m iħt 1+ 2m(4x) (15.50)

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