wegoki

A pair of charged conducting plates produces a uniform field of 12,000 N/C directed to the right, between the plates. The separation of the plates is 40 mm. In the figure, an electron is projected from plate A, directly toward plate B, with an initial velocity of 2.0 x 10^7 m/s. The velocity of the electron as it strikes plate B is closest to:

A pair of charged conducting plates produces a uniform field of 12,000 N/C directed to the right, between the plates. The separation of the plates is 40 mm. In the figure, an electron is projected from plate A, directly toward plate B, with an initial velocity of 2.0 x 10^7 m/s. The velocity of the …

A pair of charged conducting plates produces a uniform field of 12,000 N/C directed to the right, between the plates. The separation of the plates is 40 mm. In the figure, an electron is projected from plate A, directly toward plate B, with an initial velocity of 2.0 x 10^7 m/s. The velocity of the electron as it strikes plate B is closest to: Read More »

When 1.0-µC point charge is 15 m from a second point charge, the force each one experiences a force of 1.0 µN. What is the magnitude of the second charge? (k = 1/4πε0 = 9.0 × 109 N • m2/C2)

When 1.0-µC point charge is 15 m from a second point charge, the force each one experiences a force of 1.0 µN. What is the magnitude of the second charge? (k = 1/4πε0 = 9.0 × 109 N • m2/C2) EXPERT ANSWER F = K*q1*q2 / r^2 q2 = F*r^2 / k*q1 = 1.0 µN …

When 1.0-µC point charge is 15 m from a second point charge, the force each one experiences a force of 1.0 µN. What is the magnitude of the second charge? (k = 1/4πε0 = 9.0 × 109 N • m2/C2) Read More »

Two tiny particles carrying like charges of the same magnitude are 1.0mm apart. If the electric force on one of them is 5.0N what is the magnitude of the charge on each of these particles?(k = 9.0

Two tiny particles carrying like charges of the same magnitude are 1.0mm apart. If the electric force on one of them is 5.0N what is the magnitude of the charge on each of these particles?(k = 9.0 EXPERT ANSWER Given, F=5.0 N d=1.0 mm=0.001 m k=9.0*109 F=kq1q2/d2 Here, q1=q2=q F=kq2/d2 5.0=9*109*q2/0.0012 q=2.4*10-8 C Hence, C. is correct …

Two tiny particles carrying like charges of the same magnitude are 1.0mm apart. If the electric force on one of them is 5.0N what is the magnitude of the charge on each of these particles?(k = 9.0 Read More »

A proton is placed in an electric field of intensity 800 N/C. What are the magnitude and direction of the acceleration of the proton due to this field? (e = 1.60 × 10-19 C, mproton = 1.67 × 10-27 kg) A proton is placed in an electric field of intensity 800 N/C. What are the magnitude and direction of the acceleration of the proton due to this field? (e = 1.60 × 10-19 C, mproton = 1.67 × 10-27 kg)

A proton is placed in an electric field of intensity 800 N/C. What are the magnitude and direction of the acceleration of the proton due to this field? (e = 1.60 × 10-19 C, mproton = 1.67 × 10-27 kg) A proton is placed in an electric field of intensity 800 N/C. What are the …

A proton is placed in an electric field of intensity 800 N/C. What are the magnitude and direction of the acceleration of the proton due to this field? (e = 1.60 × 10-19 C, mproton = 1.67 × 10-27 kg) A proton is placed in an electric field of intensity 800 N/C. What are the magnitude and direction of the acceleration of the proton due to this field? (e = 1.60 × 10-19 C, mproton = 1.67 × 10-27 kg) Read More »

) A small 0.050-kg insulating sphere carries a charge of -60 µC and is hanging by a vertical silk thread from a fixed point in the ceiling. An external uniform vertical electric field is now applied. If the applied electric field has a magnitude of 3000 N/C and is directed downward, what is the tension in the silk thread? (k = 1/4πε0 = 9.0 × 109 N · m2/C2)

) A small 0.050-kg insulating sphere carries a charge of -60 µC and is hanging by a vertical silk thread from a fixed point in the ceiling. An external uniform vertical electric field is now applied. If the applied electric field has a magnitude of 3000 N/C and is directed downward, what is the tension …

) A small 0.050-kg insulating sphere carries a charge of -60 µC and is hanging by a vertical silk thread from a fixed point in the ceiling. An external uniform vertical electric field is now applied. If the applied electric field has a magnitude of 3000 N/C and is directed downward, what is the tension in the silk thread? (k = 1/4πε0 = 9.0 × 109 N · m2/C2) Read More »

The electric potential at a distance of 4 m from a certain point charge is 200 V relative to infinity. What is the potential (relative to infinity) at a distance of 2 m from the same charge?

The electric potential at a distance of 4 m from a certain point charge is 200 V relative to infinity. What is the potential (relative to infinity) at a distance of 2 m from the same charge? EXPERT ANSWER Given V = k*q/4 = 200 then k*q/2 = 400 therefore potential at 2m V = …

The electric potential at a distance of 4 m from a certain point charge is 200 V relative to infinity. What is the potential (relative to infinity) at a distance of 2 m from the same charge? Read More »

A metal sphere of radius 10 cm carries an excess charge of +2.0 μC. What is the magnitude of the electric field 5.0 cm above the sphere’s surface? (k = 1/4πε0 = 9.0 × 109 N • m2/C2)

A metal sphere of radius 10 cm carries an excess charge of +2.0 μC. What is the magnitude of the electric field 5.0 cm above the sphere’s surface? (k = 1/4πε0 = 9.0 × 109 N • m2/C2) 4.0 × 105 N/C 8.0 × 105 N/C 4.0 × 109 N/C 8.0 × 107 N/C 4.0 × 107 N/C EXPERT ANSWER

A small object with a 5.0-μC charge is accelerating horizontally on a friction-free surface at 0.0050 m/s2 due only to an electric field. If the object has a mass of 2.0 g, what is the magnitude of the electric field?

A small object with a 5.0-μC charge is accelerating horizontally on a friction-free surface at 0.0050 m/s2 due only to an electric field. If the object has a mass of 2.0 g, what is the magnitude of the electric field? EXPERT ANSWER F = ma = qE 2 * 10^-3 * 0.005 = 5 *10^-6 …

A small object with a 5.0-μC charge is accelerating horizontally on a friction-free surface at 0.0050 m/s2 due only to an electric field. If the object has a mass of 2.0 g, what is the magnitude of the electric field? Read More »