## EXPERT ANSWER

6)

a) V = U + g*t where U – initial velocity

b) h = ut + .5gt^2

300 = 30t + .5* 32.17*t^2

t = 3.49 sec

7) h = u^2 /2g = 250^2/(2*32.17) = 971.4 ft

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# 6. A body is dropped from a height of 300ft with an initial velocity of 30 ft /sec. Assuming no air resistance, (a) find an expression for the velocity of the body at any time t; (b) find the time r(1u1red for the body to hit the ground. 7. A ball is propelled straight up with an initial velocity of 250 ft/sec in a vacuum with no air resistance. How high will it go ?

## EXPERT ANSWER

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6)

a) V = U + g*t where U – initial velocity

b) h = ut + .5gt^2

300 = 30t + .5* 32.17*t^2

t = 3.49 sec

7) h = u^2 /2g = 250^2/(2*32.17) = 971.4 ft