**EXPERT ANSWER**

**Given:** Diameter of pipe, D=5 cm=0.05 m

Flowrate of water, Q=6 L/s=0.006 m^{3}/s

Total length of pipe, L=Horizontal length+Vertical length= 80m+9m=89 m

Elevation at point 2, z_{2} =4 m

Loss coefficient for sharp edged entrance, K_{L, entrance}=0.5

Loss coefficient for standard flanged elbow, K_{L, elbow} =0.3

Loss coefficient for gate valve (fully open), K_{L, valve} =0.2

Loss coefficient for exit, K_{L, exit} =1.06

**Assumptions:**

- Steady state and incompressible flow.
- There are no pumps or turbines included in the system. Thus loss due to turbine or pump is neglected.
- The elevations remain constant.

Both the points is open to atmosphere, thus the pressure is P_{1}=P_{2}=P_{atm}. The velocity of fluid at point 1 and 2, V_{1}=V_{2}=0.

The energy equation for the control volume system is